View Issue Details
| ID | Project | Category | Date Submitted | Last Update | |
|---|---|---|---|---|---|
| 0003849 | AI War 1 / Classic | Suggestion - New Features | Sep 18, 2011 11:27 pm | Sep 19, 2011 7:54 am | |
| Reporter | twinnuke | Assigned To | Chris_McElligottPark | ||
| Status | closed | Resolution | not fixable | ||
| Summary | 0003849: Overlapping Shield Rendering Idea | ||||
| Description | Instead of displaying all the shields and not being able to see anything underneath when you turtle up against an incoming wave why not have it select the shields that spread the farthest out, render them and only the the parts that are around the perimeter and not crossing over another shield. (Example Below) To indicate which shields are being displayed have an orange outline around the edge of the shield icon/sprite(model). Adding text below the shields (when zoomed in upon) could display their current health out of 100% (as seen in example below). I'd imagine this could be accomplished by setting up an array for shields on each planet. This Array could be recreated every time a new shield is created or an old one destroyed. The Largest shields would be given the lowest values (first positions in the array). Then you could do a radius collision detection on their shield size double radius1, radius2; (SAMPLE CODE) //calculate radius 1 if (width > height) radius1 = (width * scaling) / 2.0; else radius1 = (height * scaling) / 2.0; //center point 1 double x1 = x + radius1; double y1 = y + radius1; D3DXVECTOR2 vector1( (float)x1, (float)y1); //calculate radius 2 if (tempElement->width > tempElement->height) radius2 = (tempElement->width * tempElement->scaling) / 2.0; else radius2 = (tempElement->height * tempElement->scaling) / 2.0; //center point 2 double x2 = tempElement->x + radius2; double y2 = tempElement->y + radius2; D3DXVECTOR2 vector2( (float)x2, (float)y2); //calculate distance double deltax = vector1.x - vector2.x; double deltay = vector2.y - vector1.y; double dist = sqrt((deltax * deltax) + (deltay * deltay)); //return distance comparison (true = collision) if ((dist < radius1 + radius2) >= 1) collision = true; (/SAMPLE CODE)Sorry this is from my Associate's Project in C++. This is where I am inexperienced (I have yet to do much rendering coding beyond simple sprites/rotation/frame changing and what not) You would then not render the part of the sprite that is overlapping on either sprite. I would look more into this but I have to finish other projects before I learn more about this. - Ken | ||||
| Tags | No tags attached. | ||||
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While I'd love for this to happen, I fear it might be a bit too processor intensive. |
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Uhm, last I checked shields already did not display when overlapping. What changed? |
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Shields definitely display when overlapping and, as far as I know, always have. |
| Date Modified | Username | Field | Change |
|---|---|---|---|
| Sep 18, 2011 11:27 pm | twinnuke | New Issue | |
| Sep 18, 2011 11:27 pm | twinnuke | File Added: shield update.png | |
| Sep 18, 2011 11:36 pm | twinnuke | Description Updated | |
| Sep 19, 2011 6:47 am | Toll | Note Added: 0013240 | |
| Sep 19, 2011 7:06 am | Ranakastrasz | Note Added: 0013241 | |
| Sep 19, 2011 7:08 am | Toll | Note Added: 0013242 | |
| Sep 19, 2011 7:54 am | Chris_McElligottPark | Status | new => closed |
| Sep 19, 2011 7:54 am | Chris_McElligottPark | Assigned To | => Chris_McElligottPark |
| Sep 19, 2011 7:54 am | Chris_McElligottPark | Resolution | open => not fixable |
